Understanding Simple Kinematics: Solving for Velocity in Resisted Motion

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The discussion focuses on solving for velocity in resisted motion where the retarding force is proportional to velocity, represented by the equation Fr = -kmv. The initial approach using the kinematic equation v = vo + at is deemed inappropriate because acceleration is not constant in this scenario. Instead, the correct method involves using calculus to derive the velocity function, leading to v = vo * e^(-kt) after applying initial conditions. This highlights the importance of recognizing that the changing force results in variable acceleration, which invalidates the use of constant acceleration equations. Understanding this distinction is crucial for accurately solving problems in kinematics involving resistance.
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Homework Statement


I should know this, but it's been awhile since I've dealt w/ kinematics.

As the simplest example of resisted motion of a particle, find the velocity of horizontal motion in a medium in which the retarding force is proportional to velocity.

So Fr is something like -kmv, where k is a constant.

I'm tempted to use v=vo+at in this manner:

ma=-kmv, so a = -kv
then v=vo-kvt
v(1+kt)=vo
v=vo/(1+kt)

But my book uses integrals:
mdv/dt=-kmv
int(dv/v)=-k*int(dt)
lnv=-kt+C , v= c1e^-kt where (c1=e^C) and applying initial conditions you get
v=vo*e^-kt
and this makes a lot of sense to me.

So could somebody please refresh me on why I cannot solve for a and substitute into v=vo+at? I'm thinking it has to do with the constantly changing force, but I'm looking for a good explanation.
 
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Kinematic equation v = vo + at is applicable to a motion having constant acceleration. But in the given problem acceleration is not constant.
 
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