Understanding Symbols in Physics Equations: What Do They Mean?

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The discussion focuses on understanding the notation in physics equations, specifically the use of "exp" and brackets. "Exp(x)" represents the exponential function, equivalent to "e^x," and is preferred for complex arguments. Brackets indicate separate calculations, similar to parentheses. The conversation also touches on programming applications, illustrating how to use exponential functions in Java. Overall, the thread clarifies the meaning and utility of these symbols in mathematical expressions.
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Homework Statement


I have been reading a lot about physics and equation that look like the photo I attached. What do the brackets and the EXP mean?


Homework Equations





The Attempt at a Solution

 

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I cannot see the attached image, however, if you mean something like this: \exp (x) that is just the exponential function, so \exp(x) = e^x

It's just a more convenient way of representing the function when its arguments start to get complicated
 
The brackets are just that- a way of indicating a separate calculation, no different from parentheses.
 
matineesuxxx said:
I cannot see the attached image, however, if you mean something like this: \exp (x) that is just the exponential function, so \exp(x) = e^x

It's just a more convenient way of representing the function when its arguments start to get complicated
HallsofIvy said:
The brackets are just that- a way of indicating a separate calculation, no different from parentheses.
Here is a better picture
ImageUploadedByPhysics Forums1407259101.931582.jpg

If someone could write it without EXP that would be great so that I know what you guys are talking about.
 
The exp() notation is useful though if you are writing an expression in some programming languages such as Java where

Code:
double x = 3.2;
double y = Math.exp(x);       // refers to the e^x math function

For more general exponentiation then:

Code:
double x =3.2;
double y = 4.3;
double z = Math.pow(x,y);     // for x^y math function
 
Last edited:
##I = C_1 + C_2 G - C_3(e^{\frac {V} {C_4T_{cc}}} - 1) - C_5(e^{\frac {V} {C_6T_{cc}}} - 1) - \frac {V} {C_7T_{cc}}##
 
AlephZero said:
##I = C_1 + C_2 G - C_3(e^{\frac {V} {C_4T_{cc}}} - 1) - C_5(e^{\frac {V} {C_6T_{cc}}} - 1) - \frac {V} {C_7T_{cc}}##

Where are you getting the e? Is that euler's number?
 
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