Understanding Ternary Phase Diagrams for Inverted Micelle Formation

AI Thread Summary
The discussion focuses on interpreting ternary phase diagrams for inverted micelle formation, specifically how to determine the composition of components like NaC(8), water, and C(10)OH. To find the composition of 9% NaC(8), 28% water, and 63% C(10)OH, one must draw lines parallel to the axis opposite the vertex of the substance being analyzed. This method highlights the area relevant to inverted micelles and the minimum required amount of C(10)OH. The left axis represents C(10)OH, the right axis represents water, and the bottom axis represents NaC(8). The discussion reflects a learning experience about the complexities of reading such diagrams.
kasse
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Will someone please explain how one can read from this diagram that the composition is 9% NaC(8), 28% water and 63% C(10)OH when we have the smallest amount of C(10)OH to have inverted micelles in the system?
 
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I believe you have to draw three lines, parallel to the axis opposite the vertex of the substance you are interested and going through the point in question. Here since you are interested in inverse micelle and lowest composition in C10OH it responds to the area i marked.

inversemicelle.jpg


The left axis is C10OH , right is H2O and the bottom is NaC8.

P.S. I just googled it tbh, never seen a diagram like that before and it seemed interesting. So i might as well be wrong. You can read about it http://www.sv.vt.edu/classes/MSE2094_NoteBook/96ClassProj/experimental/ternary2.html" .
 
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