Understanding the Brightness of Light Globes in Series Circuits

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When only light globe Sa is switched on, the total resistance of the circuit remains unchanged, and the current is evenly split between the two globes, resulting in reduced brightness for each. Conversely, if only globe Sb is switched on, it effectively short circuits the circuit, causing the other globe to turn off completely as all current flows through Sb. The discussion emphasizes that the total resistance does not change when switching between the globes, impacting how current is distributed. Participants clarify that the current divides equally in a parallel circuit configuration, affecting the brightness of the globes. Understanding these principles is crucial for analyzing the behavior of light globes in series circuits.
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Homework Statement


1. Describe and explain how the brightness of each globe will be affected if only Sa is switched on.
2. Describe and explain the effects of the light globes if only Sb is switched on.


Homework Equations


None


The Attempt at a Solution


No working out required I believe.
 

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If only Sa is closed, what happens to the total resistance of the circuit?
What is the current in each lamp?
If Sb is closed, What change in the resistance you observe in the circuit?
 
for when Sa is closed,the total resistance doesn't change because their was current flowing through the globes but from a different path, current in each lamp would decrease because it is being split up now that there is an extra path?
 
TyErd said:
for when Sa is closed,the total resistance doesn't change because their was current flowing through the globes but from a different path, current in each lamp would decrease because it is being split up now that there is an extra path?
It is not correct. Since the total resistance remains the same, the current drawn from the cell is the same. In both the cases , it equally branches out in two parallel circuits. So in each the branch the current is I/2.
 
Okay, i understand, now for when only Sb is closed,...im not really sure
 
TyErd said:
Okay, i understand, now for when only Sb is closed,...im not really sure
One bulb is short circuited. Leaving that bulb, calculated the total resistance and the current in each bulb.
 
why is it short circuited?
 
TyErd said:
why is it short circuited?
All the current passes through the Sb. So the bulb will be off.
 
does all current pass through Sb or does it divide into two paths?
 

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