Understanding the Lorentz Transformation Equation for Time

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cr41g
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Suppose an inertial frame of reference S’ moves at a constant velocity v in the
positive x-direction with respect to a second inertial frame S. The Lorentz
transformation from S to S’ for the x coordinate of displacement is given by:
x′ =γ (x − vt)
Write down a corresponding expression for the inverse transformation, i.e. from
S’ to S, giving x in terms of x’ and t’.
Use these two expressions to derive the Lorentz transformation equation for time:

t'=γ(t-vx/c^2)


I think I have the first part, I answered x =γ (x' + vt). But the second part I have no idea I have been looking online and even watching lectures on youtube.
Thanks in advance.
 
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Sorry vt'

Do you know the second part or even where I should start?
 
X' I think. Sorry if I sound a bit stupid. I'm in my first year and this is only my second question.
 
Take your answer for the first part, substitute in for x' in terms of x and t, then solve for t' in terms of x and t.
 
Ok I've done what you have said and got-

t'=(x+γ(γx-γvt))/γv

Now I am competent lost
 
Can anyone actually show me this step as I am completely thrown. I just can't make sense of it.
 
Yeah I found that when I started from scratch. But I'm still at a loss. It just looks a mess. Do you expand all the gammas?
 
Collect your x and t terms. The t term should fall out straight away. That leaves the x term. I'd suggest that if in doubt, expand, is a good rule of thumb here. You might want to use [itex]\beta=v/c[/itex] to save ink.
 
Ok. Well just got into bed so I will give it a go before I go to university tomrrow. Thanks for your help guys.
 
Yeah as far as I'm aware no hate when algebra is explained in words. But yeah I think I did.