Understanding the Lorentz Transformation Equation for Time

AI Thread Summary
The discussion revolves around deriving the Lorentz transformation equation for time, starting from the transformation of the x coordinate. The initial transformation from frame S to S’ is given as x′ = γ(x − vt), and participants are tasked with finding the inverse transformation, x = γ(x' + vt). The main challenge lies in deriving the time transformation equation t' = γ(t - vx/c²) from these expressions. Participants express confusion over simplifying the equations and correctly substituting variables. Ultimately, the conversation emphasizes the importance of algebraic manipulation and understanding the relationships between the variables involved.
cr41g
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Question
Suppose an inertial frame of reference S’ moves at a constant velocity v in the
positive x-direction with respect to a second inertial frame S. The Lorentz
transformation from S to S’ for the x coordinate of displacement is given by:
x′ =γ (x − vt)
Write down a corresponding expression for the inverse transformation, i.e. from
S’ to S, giving x in terms of x’ and t’.
Use these two expressions to derive the Lorentz transformation equation for time:

t'=γ(t-vx/c^2)


I think I have the first part, I answered x =γ (x' + vt). But the second part I have no idea I have been looking online and even watching lectures on youtube.
Thanks in advance.
 
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vt? Are you sure?
 
Sorry vt'

Do you know the second part or even where I should start?
 
You've got x' in terms of x and t, and x in terms of x' and t'. Which variable don't you want to appear in the final expression?
 
X' I think. Sorry if I sound a bit stupid. I'm in my first year and this is only my second question.
 
Take your answer for the first part, substitute in for x' in terms of x and t, then solve for t' in terms of x and t.
 
Ok I've done what you have said and got-

t'=(x+γ(γx-γvt))/γv

Now I am competent lost
 
Completely*
 
This is correct, you just need to simplify it. What is γ equal to?
 
  • #10
Expand the Lorentz gammas and collect terms. Courage! This one always looks a mess to me until it all clicks into place at the end.
 
  • #11
Can anyone actually show me this step as I am completely thrown. I just can't make sense of it.
 
  • #12
You have a sign wrong in your expression for t', I just noticed. That might be your problem.
 
  • #13
Yeah I found that when I started from scratch. But I'm still at a loss. It just looks a mess. Do you expand all the gammas?
 
  • #14
Collect your x and t terms. The t term should fall out straight away. That leaves the x term. I'd suggest that if in doubt, expand, is a good rule of thumb here. You might want to use \beta=v/c to save ink.
 
  • #15
Ok. Well just got into bed so I will give it a go before I go to university tomrrow. Thanks for your help guys.
 
  • #16
When you studied algebra, did they teach you how to solve 2 linear algebraic equations in two unknowns?
 
  • #17
Yeah as far as I'm aware no hate when algebra is explained in words. But yeah I think I did.
 
  • #18
cr41g said:
Yeah as far as I'm aware no hate when algebra is explained in words. But yeah I think I did.
If that is the case, that's all you have to do in this problem. Your two unknowns are x and t. Solve for 'em.

Chet
 
  • #19
Thank you
 
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