Understanding the One Dimensional Wave Equation

AI Thread Summary
The One Dimensional wave equation is given by ∂²y(x,t)/∂x² = (1/v²) ∂²y(x,t)/∂t². The function y(x,t) = ln(b(x-vt)) is proposed as a solution to this equation. To verify this, one must substitute ln(b(x-vt)) into the wave equation and perform partial differentiation with respect to x and t. The results of these differentiations should then be compared to see if they satisfy the original wave equation. This method is confirmed as correct for determining if the function is indeed a solution.
OnceKnown
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Homework Statement

Given that the the One Dimensional wave equation is \frac{∂^{2}y(x,t)}{∂x^{2}} = \frac{1}{v^{2}} \frac{∂^{2}y(x,t)}{∂t^{2}} is y(x,t) = ln(b(x-vt)) a solution to the One Dimensional wave equation?

Homework Equations

Shown above.

The Attempt at a Solution

So my Professor stated that yes, it was a solution to the One Dimensional Wave equation, but I am confused on the process to get this answer. Do we plug the ln(b(x-vt)) into the y(x,t) of the equation and then using partial differentiation to solve in terms of "x" and "t" and see if they match the original equation?
 
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OnceKnown said:
Do we plug the ln(b(x-vt)) into the y(x,t) of the equation and then using partial differentiation to solve in terms of "x" and "t" and see if they match the original equation?


Yes, that is a right method.
 
OnceKnown said:
Do we plug the ln(b(x-vt)) into the y(x,t) of the equation and then using partial differentiation to solve in terms of "x" and "t" and see if they match the original equation?

Yes, that is a right method.
 
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