Understanding the Relativistic Velocity Equation

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A particle moving at 0.4c in frame S' and frame S' itself moving at 0.6c relative to frame S requires the relativistic velocity equation for accurate calculation. The user initially misapplied the equation by not converting velocities to their respective units in terms of c. After clarification, it was confirmed that using u' = 0.4c and v = 0.6c yields the correct result of 0.81c for the particle's velocity in frame S. The discussion highlights the importance of proper unit conversion in relativistic physics. Understanding these conversions is crucial for accurate calculations in relativistic scenarios.
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A particle moves along the x' axis of frame S' with velocity .4c. Frame S' moves with velocity .6c with respect to frame S. What is the velocity of the particle with respect to frame S'?

I used the realistic velocity equation:
u=(u' + v)/(1+u'v/c^2)

u=(.4 + .6)/(1+.4*.6/(3*10^8)^2)

The answer I get is 1 but the real answer is .81c

What am I doing wrong?

Thanks
 
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You are using u' = .4 and v = .6 instead of u' = .4c = .4*3*10^8 and v = .6c = .6*3*10^8.
 
I see. I keep thinking c is a unit of measurement. It all works now. Thanks!
 
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