Understanding Vector Addition: 2 Forces with Same Magnitude F

AI Thread Summary
Two forces with the same magnitude F can yield different resultant magnitudes depending on the angle between them. If their sum is 2*F, the angle is 60 degrees, derived from the equation cosθ = 1/2. For a resultant magnitude of sqrt(2)*F, the angle is 45 degrees, calculated using cosθ = 1/sqrt(2). If the resultant magnitude is zero, the vectors are opposite in direction, resulting in an angle of 180 degrees. Understanding these relationships is crucial for vector addition and angle determination.
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Two forces have the same magnitude F. What is the angle between the two vectors if their sum has a magnitude of 2*F? sqrt(2)*F? zero?
 
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How about using the triangle vector adition method? and then applying cosine law to it to find the angle between F and F? or better yet use the paralellogram vector adittion method.
 
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To find the angle between two vectors, we can use the formula cosθ = (A·B)/(|A||B|), where A and B are the two vectors and θ is the angle between them. In this case, we know that the magnitude of both vectors is F, so we can simplify the formula to cosθ = (A·B)/F^2.

For the first case, where the sum of the two vectors has a magnitude of 2*F, we can set up the equation |A + B| = 2*F and solve for cosθ. This will give us cosθ = 1/2, which means that the angle between the two vectors is 60 degrees.

For the second case, where the sum of the two vectors has a magnitude of sqrt(2)*F, we can set up the equation |A + B| = sqrt(2)*F and solve for cosθ. This will give us cosθ = 1/sqrt(2), which means that the angle between the two vectors is 45 degrees.

Lastly, if the sum of the two vectors has a magnitude of zero, this means that the two vectors are equal in magnitude but opposite in direction. In this case, the angle between the two vectors is 180 degrees.

I hope this helps guide you in the right direction. Remember to always use the formula cosθ = (A·B)/(|A||B|) when trying to find the angle between two vectors with known magnitudes.
 
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