Uniform circular motion on a table

In summary, the conversation discusses a problem involving a small block on a frictionless tabletop connected to a larger block through a string passing through a hole. The small block is in uniform circular motion with radius r and speed v. The question is asking for the velocity at which the larger block is neither rising nor falling, and the solution involves the equation m_1 a = \frac{m_2 v^2}{r} where m_1 is greater than m_2.
  • #1
cj3
4
0

Homework Statement


A small block with mass m rests on a frictionless horizontal tabletop a distance r from a hole in the center of the table. A string tied to the small block passes down through the hole, and a larger block with mass M is suspended from the free end of the string. The small block is set into uniform circular motion with radius r and speed v.


Homework Equations


a=v2/R
F=ma

The Attempt at a Solution


I really have know idea...but here goes nothing
Mg=Ma
Mg=Mv2/r
g=v2/r
v=sqrt(g/r)
 

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  • #2
What is the question..? That is just a statement.
I assume they are asking for the velocity at which larger block is neither rising nor falling?
 
  • #3
yes, sorry, that's what theyre looking for
 
  • #4
You have got the right idea with the equation, by letting [tex] ma = \frac{mv^2}{r} [/tex]

however this is where the error is. You canceled the masses. You can't do this because the question specifically states that the mass hanging on the bottom of the string is larger than that on the table.

So your equation is now: [tex] m_1 a = \frac{m_2 v^2}{r} [/tex] where [tex] m_1 > m_2 [/tex]

Solve for v.
 

What is uniform circular motion on a table?

Uniform circular motion on a table refers to an object moving in a circular path at a constant speed on a flat surface, such as a table. This motion is characterized by the object's velocity being constantly perpendicular to the radius of the circle.

What is the centripetal force in uniform circular motion on a table?

The centripetal force in uniform circular motion on a table is the force that acts towards the center of the circle, keeping the object in its circular path. This force is necessary to counteract the object's tendency to move in a straight line, as described by Newton's First Law of Motion.

What are the factors that affect the centripetal force in uniform circular motion on a table?

The factors that affect the centripetal force in uniform circular motion on a table include the mass of the object, the speed of the object, and the radius of the circular path. The greater the mass or speed of the object, or the smaller the radius, the greater the centripetal force required to maintain the motion.

How can you calculate the centripetal force in uniform circular motion on a table?

The centripetal force in uniform circular motion on a table can be calculated using the equation F = mv²/r, where F is the centripetal force, m is the mass of the object, v is the speed of the object, and r is the radius of the circular path.

What are some real-life examples of uniform circular motion on a table?

Some real-life examples of uniform circular motion on a table include a coin rolling in a circular motion on a tabletop, a toy car moving around a circular racetrack, or a record spinning on a turntable. Other examples include the motion of a satellite orbiting the Earth and the motion of planets around the Sun.

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