Units of C(p) and C(v) in equation (1) are Joule/Kilogram-Kelvin.

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The discussion focuses on the units of specific heat capacities C(p) and C(v) in Mayer's equation, which states that C(p) – C(v) = R. It emphasizes that for the equation to be valid, the units of C(p) and C(v) must match the units of the universal gas constant R. When R is divided by J, it converts R from a work unit to a heat unit, specifically to Calorie/mole.Kelvin. This conversion is essential for maintaining consistency in the equation. Understanding these unit relationships is crucial for applying Mayer's equation correctly in thermodynamics.
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Homework Statement


1) According to Mayer’s equation,
C(p) – C(v) = R ------------ (1)
Where C(p) = specific heat at constant pressure
C(v) = specific heat at constant volume
R = Universal gas constant
But sometimes the above equation is used in the following way,
C(p) – C(v) = R/J ---------------- (2)
Where C(p) = gram molecular specific heat of the gas at constant pressure
C(v) = gram molecular specific heat of the gas at constant volume
R = Universal gas constant
J = Mechanical equivalent of heat



Homework Equations





The Attempt at a Solution



What are the units of C(p) & C(v) in equation(1)?
 
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because the units on the two sides of the equation must match in order for the equation to be valid, the units of C_p and C_v must be the same as the units for the universal gas constant R.
 
If we divide R by J then the unit of R will be Calorie/mole.Kelvin. So by doing this we change the unit of R from work unit to heat unit, isn't it?
 
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