What Are the Correct Units of Coulomb's Constant?

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Coulomb's constant, used in Coulomb's Law, incorporates the permittivity of free space (ε0), which has units of F/m. There is a debate on whether the units of Coulomb's constant should be expressed as F/m or F^-1m. Some argue that since Coulomb's constant (ke) is defined as 1/(4∏ε0), it implies a different unit interpretation. Further clarification reveals that the unit of ε0 can also be expressed in basic SI units as A²s⁴kg⁻¹m⁻³. The discussion emphasizes the complexity of deriving units in electrostatics.
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Coulomb's constant, which appears in Coulomb's Law, contains ε0.

The units of ε0 being F/m

Are the units of Coulomb's constant therefore F/m ?

Thank you.
 
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ZedCar said:
Coulomb's constant, which appears in Coulomb's Law, contains ε0.

The units of ε0 being F/m

Are the units of Coulomb's constant therefore F/m ?

Thank you.

I would have thought F-1m since ke = 1/(4∏εo)
 
ZedCar said:
Coulomb's constant, which appears in Coulomb's Law, contains ε0.

The units of ε0 being F/m

Are the units of Coulomb's constant therefore F/m ?

Thank you.

Yes, but farad can be derived from the basic units of the SI system, so the unit of ε0 is A2s4kg-1m-3 in terms of the basic SI units.

ehild
 
PeterO said:
I would have thought F-1m since ke = 1/(4∏εo)

For parallel plate capacitors, C=εA/d (A is the surface of the plates, d is the distance between them) so farad=[ε]m.

ehild
 
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