Upcoming Physics Olympiad Test

In summary, the question asks for the minimum velocity v0 needed for a bullet of mass m to strike a pendulum of mass M and complete a circular vertical loop with length L. The relevant equations are p=mv, KE=1/2 mv^2, and PE=mgh. The minimum velocity can be found by setting up an equation of forces and using the concepts of circular motion. The actual answer is vo=((m+M)sqrt(5Lg))/m.
  • #1
physics517
7
0

Homework Statement



Abullet of mass m strikes a pendulum of mass M suspended from a pivot by a string of length L with a horizontal velocity v0. The collision is perfectly INelastic and the bullet sticks to the bob. Find the minimum velocity v0 such that the bob (with the bullet inside) completes a sircular vertical loop


Homework Equations



p=mv

KE=1/2 mv^2

PE=mgh

The Attempt at a Solution



mvo=(m+M)vf

mg(2L)=1/2 m vf^2 --------- This is the Vf needed to comlete one whole loop (also i think this is where I am missing something)

vf=2 sqrt(Lg)

and so the answer i got was vo= ((m+M)2 sqrt(Lg)) / m

but the ACTUAL asnwer is vo= ((m+M) sqrt(5Lg)) / m
 
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  • #2
What equations are relevant? Where's your attempt at a solution?

By the way, your post title is pretty unspecific about the actual problem content.
 
  • #3
physics517 said:
mg(2L)=1/2 m vf^2 --------- This is the Vf needed to comlete one whole loop (also i think this is where I am missing something)
Indeed. That is NOT the velocity needed to complete one loop, that is the minimum velocity required for the bob (and bullet) to just reach the top of the circular loop. For the bob and bullet to complete a circular loop, it cannot have zero velocity at the top of the loop! There is a minimum velocity that it must possesses - think back to your concepts of circular motion.
 
  • #4
Lol I shouldve drew a diagram.

so up top its F+mg=mv^2/r and the F (tension) cancels out since we're trying to find minimum speed. so v=sqrt(gr) and if we go back to my original work equation

it should be 1/2 m vf^2 = mgh + 1/2 m vtop ^2

then you find the Vf and then plug that into the momentum equation

Thanks so much guys!
 
  • #5



I would first commend the student for their attempt at solving the problem and using the correct equations. However, there seems to be a mistake in the calculation of the final velocity needed to complete the circular loop. The correct expression for the final velocity should be vf=sqrt(5Lg), which can be derived from the conservation of energy equation. Therefore, the minimum velocity v0 should be vo= ((m+M)sqrt(5Lg))/m. I would also suggest the student to double check their calculations and equations to ensure accuracy in their solution. Additionally, it would be helpful to explain the reasoning behind the use of the conservation of energy equation in this problem, as it is a key concept in solving many physics problems. Overall, the student has shown a good understanding of the concepts involved in this problem and with some minor adjustments in their calculations, they can arrive at the correct solution.
 

Related to Upcoming Physics Olympiad Test

What is the format of the upcoming Physics Olympiad Test?

The upcoming Physics Olympiad Test will most likely consist of multiple-choice questions, free response questions, and possibly some hands-on experimental tasks. It will cover various topics in physics such as mechanics, thermodynamics, electricity and magnetism, optics, and modern physics.

How can I prepare for the upcoming Physics Olympiad Test?

To prepare for the upcoming Physics Olympiad Test, it is important to have a strong foundation in physics concepts and principles. Practice solving problems from previous Physics Olympiad tests and familiarize yourself with different question formats. It is also helpful to study with a group or seek guidance from a mentor or teacher.

What is the level of difficulty for the upcoming Physics Olympiad Test?

The level of difficulty for the upcoming Physics Olympiad Test will be challenging, as it is designed to test the knowledge and problem-solving skills of high school students. However, with proper preparation and dedication, it is possible to perform well on the test.

What are the benefits of participating in the Physics Olympiad Test?

Participating in the Physics Olympiad Test allows students to showcase their knowledge and skills in physics, as well as compete with other students on a national or international level. It also provides an opportunity to learn from and interact with other like-minded individuals and potentially open doors for future academic and career opportunities in the field of physics.

How is the upcoming Physics Olympiad Test scored?

The upcoming Physics Olympiad Test will most likely be scored based on the number of correct answers and possibly partial credit for free response questions. A higher score will indicate a better understanding and mastery of physics concepts and principles.

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