Urgent: Interfering Waves Homework: Find Speed in Regions A & B

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The discussion focuses on calculating the speed of water waves in two regions of a ripple tank, using a plane wave generator with a frequency of 60.0 Hz and a wavelength of 3.0 cm. The speed in region A is calculated to be 3.14 m/s, while the speed in region B is determined to be 1.03 m/s, based on Snell's law and the relationship between wave speed, frequency, and wavelength. The calculations confirm that the speed in region A is consistent with the initial velocity derived from the frequency and wavelength. The application of Snell's law effectively relates the wave speeds in both regions. Overall, the solution appears accurate and well-supported by the provided equations.
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Homework Statement


A plane wave generator with a freqenecy of 60.0Hz creates a water wave of wavelength 3.0cm in region A of a ripple tank. The angle between the wave crests and straight boundary between regions A and B is 25.0 degrees in region A and 14.0 degrees in region B. Find the speed of the wave in each region.

f = 60.0Hz
lambda = 0.030 m
thedaA = 25.0 degrees
thedaB = 14.0 degrees
vA = ?
vB = ?

Homework Equations



I was thinking to use snell's law, but I am not sure how to...

The Attempt at a Solution



General v...

v = f x lamda
v = 60 x 0.030
v = 1.8 m/s

Find vA

vA/1.8 = Sin25/Sin14
vA = 3.14 m/s

Find vB

vB/1.8 = Sin14/Sin25
vB = 1.03 m/s
 
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kevykevy said:

v = f x lamda
v = 60 x 0.030
v = 1.8 m/s


Yes, so this is already the velocity in region A.

vB/1.8 = Sin14/Sin25
vB = 1.03 m/s

This looks ok at first sight.
 

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