Use cylindrical coordinates to find volume

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SUMMARY

The discussion focuses on using cylindrical coordinates to find the volume defined by the equations x² + y² + z² = 16 and z = √(x² + y²). The user initially attempted to convert to spherical coordinates but faced challenges. The correct approach involves converting Cartesian coordinates to cylindrical coordinates using the formulas x = r cos(Ø), y = r sin(Ø), and r = √(x² + y²). The integration bounds and the setup of the volume integral in cylindrical coordinates are crucial for solving the problem accurately.

PREREQUISITES
  • Cylindrical coordinates and their properties
  • Integration techniques in multivariable calculus
  • Trigonometric identities, specifically cos²(Ø) + sin²(Ø) = 1
  • Conversion methods between Cartesian and cylindrical coordinates
NEXT STEPS
  • Practice converting Cartesian equations to cylindrical coordinates
  • Study volume integration in cylindrical coordinates
  • Learn about setting integration bounds for cylindrical coordinates
  • Explore applications of cylindrical coordinates in physics and engineering
USEFUL FOR

Students studying multivariable calculus, particularly those struggling with cylindrical coordinates and volume integration. This discussion is also beneficial for educators looking for examples to illustrate these concepts.

Carmen12
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Homework Statement


Use cylindrical coordinates to find volume...

Homework Equations

Inside: x2+y2+z2=16
Outside: z=sqrt(x2+y2)

The Attempt at a Solution



Cylindrical coordinates have always been a problem for me, so I initially tried to put them into spherical and then convert them over, but that went badly pretty quickly. Then basically integrated from 0 to 4 the inside minus the outside function but that didn't go well either... and obviously so.

So.. should I just try to convert from Cartesian to cylindrical and then integrate, but I have trouble with the bounds. :(
 
Last edited:
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In cylindrical coordinates you have 3 dimensions, r,Ø,z

The conversion from cartesian to cylindrical is

x=rCosØ
y=rSinØ
r=sqrt(x^2+y^2)

So you equation will be:

Outside:
r^2*cos^2(Ø)+r^2*sin^2(Ø)+z^2=16
=> r^2*(cos^2(Ø)+sin^2(Ø))+z^2=16 ; cos^2(Ø)+sin^2(Ø)=1 is a trigonometric identity
then

r^2+z^2=16
inside:
Z=r
 

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