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## Main Question or Discussion Point

Why do we use phasor representation in physics..For example,why we need maxwells equation in phasor form as well??

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Why do we use phasor representation in physics..For example,why we need maxwells equation in phasor form as well??

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UltrafastPED

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So you will probably only use phasors while studying AC circuits; they are useful only for linear systems.

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UltrafastPED

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In this case they assumed that the electromagnetic field was a harmonic wave - and plugged this into Maxwell's equations - leaving you with the "Phasor form of Maxwell's equations".

Here is a lecture which includes the derivation: http://ivp.ee.cuhk.edu.hk/~ele3310/data/ELE3310_Tutorial_10.pdf

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jasonRF

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[tex]

\mathbf{D} = \epsilon_0 \mathbf{E} + \mathbf{P}

[/tex]

but it is only for a single frequency that

[tex]

\mathbf{P}(\omega) = \epsilon_0 \chi_e (\omega) \mathbf{E}(\omega).

[/tex]

In the time domain we in general have a convolution,

[tex]

\mathbf{P}(t) = \epsilon_0 \int^t d\tau \, \, \, \chi_e (\tau) \mathbf{E}(t-\tau).

[/tex]

jason

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Claude Bile

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You can assume a time dependence of exp(jwt) without losing generality due to the principle of superposition. For incident fields with multiple frequency components, you can solve Maxwell's equations for each frequency component, then sum the solutions at the end as required.

Claude.

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