Use of potentiometer or rheostat to determine resistance – need clarification

AI Thread Summary
A potentiometer can effectively divide voltage to any desired level, allowing for variable voltage application across a resistor, while a rheostat, used in series, adjusts current through the resistor. Both methods yield voltage and current pairs for resistance calculation using the formula V/I = R. The potentiometer is often preferred for its ability to control voltage without significant thermal variance, which can affect measurements with a rheostat. However, the choice may depend on the resistor's size, as very low resistance values can complicate measurements regardless of the method used. Ultimately, the selection between a potentiometer and a rheostat hinges on specific measurement conditions and desired accuracy.
elvinc
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Hello

I understand

Homework Statement



1) a potentiometer can be used to divide a voltage to any value between zero and the voltage source. This can be used to place a variable voltage through a resistor

2) A rheostat (variable resistor) which is placed in series with the resistance to be measured can create a variable current through the resistor.

Now if voltage and current is measured in both setups as either the potentiometer or rheostat is changed both will generate pairs of values for voltage across and current through the resistor under test.

Homework Equations


V/I = R

The Attempt at a Solution


Plotting V against I for both sets of experiments would enable me to calculate the resistance as gradient of the plot. So which method (if one is to be preferred) should be used to determine the test resistance? Why?

Thanks,

Clive
 
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Welcome to PF.

Intuitively I would choose the potentiometer, because I could expect to want to control the voltage source across the test piece. A rheostat may have some thermal variance with different current loads (I2R), that I would expect a potentiometer would mitigate to some degree.

But in large part it depends on the size of the resistors you would be trying to measure. If they are very small values of ohms, things could be more challenging regardless of what method you would choose.

That's just me. Others may have better reasons than my intuition to choose one or the other, and if so, then by all means help the fellow out. It hasn't been addressed for half a day.
 
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