Using e in a Formula: Electric Potential

  • Thread starter Thread starter hardwork
  • Start date Start date
  • Tags Tags
    Formula
AI Thread Summary
In formulas involving electric potential, the charge of an electron is represented as -1.6x10^-19 C due to its negative charge. The work done by the electric force can be calculated using the potential difference between two points, with the formula Work = q(Va - Vc). This results in a consistent magnitude of work, regardless of whether the charge is treated as positive or negative. The key distinction lies in whether the work is considered done on the charge or by the charge. Understanding this concept is crucial for accurately calculating electric potential and work in physics.
hardwork
Messages
20
Reaction score
0
When using e (for electron) in a formula, do you use +1.6x10^-19 C or -1.6x10^-19 C?

For example:

http://i44.tinypic.com/25g9te8.jpg

An electron moved from c to a. How much work is done by the electric force?

Electric Potential
Point a = 6.2x10^5 V
Point c = -7.5x10^4 V

Work = (-1.6x10^-19 C) (Va - Vc) = -1.1x10^-13
-W(electric force) = +1.1 x 10^-13

OR

Work = (1.6x10^-19 C) (Va - Vc) = 1.1x10^-13
-W(electric force) = -1.1 x 10^-13
 
Physics news on Phys.org
Welcome to PF.

Electron carries a negative charge.
 
According to the definition of the potential difference between the two points, it is the work done on the positive charge to move it against the electric force.
So the magnitude of the work is the same. Only difference is whether it is on the charge or by the charge.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top