Using Fourier Transforms to solve Definite Integrals with Limits 0 to Infinity

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1. Using Fourier Transforms to solve Definite Integrals with Limits 0 to Infinity

I'm trying to understand how to use Fourier Transforms to solve Definite Integrals with limits from 0 to Infinity.
I understand how to use Fourier Transforms to solve indefinite integrals, but I believe there is supposed to be a much simpler way to solve these definite integrals without working out the entire indefinite solution.


Homework Equations


X(j0) = Integral from -Infinity to Infinity : x(t)dt
x(0) = Integral from -Infinity to Infinity: X(jw)dw
 
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Welcome to PF! Here's a hint: Think about even and odd time functions.
 
\displaystyle\int^\infty_0 2te^-^a^t\cos(t)\,dt = ?}

I'm not entirely sure how to manipulate this.. the e^-^a^t makes it so the function is neither even nor odd anymore.. even if I pulled the even part out to rewrite the function so its integrated from -infinity to infinity I'm unsure about what to do with the odd piece.
 
Yikes! I don't know what to do with this either. Sorry I jumped in...
 
marcusl said:
Yikes! I don't know what to do with this either. Sorry I jumped in...

I appreciate the thought! Thanks! :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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