Using Lagrangian Formulation to Solve a Mass on a Wedge Problem

  • Thread starter Thread starter bit188
  • Start date Start date
  • Tags Tags
    Lagrangian
Click For Summary
SUMMARY

The discussion focuses on solving a mechanics problem involving a wedge of mass M and angle α, with a particle of mass m sliding on it, using the Lagrangian formulation. The position of mass m is defined as x = l cos(α) and y = l sin(α), leading to the kinetic energy expression of [(1/2)m][l² cos²(α) - l² sin²(α)] and potential energy of [l sin(α)][mg]. The Lagrangian is formulated as L = [(1/2)l²m(cos²(α) - sin²(α))] - [l sin(α)][mg]. The problem emphasizes the need to account for the motion of the wedge, which introduces two independent degrees of freedom: the horizontal position of the wedge and the height of the mass on the wedge.

PREREQUISITES
  • Lagrangian mechanics
  • Kinetic and potential energy calculations
  • Coordinate transformations in physics
  • Understanding of degrees of freedom in mechanical systems
NEXT STEPS
  • Study the derivation of the Euler-Lagrange equations
  • Explore examples of constrained motion in Lagrangian mechanics
  • Learn about the implications of independent degrees of freedom in dynamic systems
  • Investigate the effects of friction on the motion of the wedge and mass
USEFUL FOR

Students and professionals in physics, particularly those studying classical mechanics, as well as educators looking for practical examples of Lagrangian formulation applications.

bit188
Messages
45
Reaction score
0

Homework Statement


A wedge of mass M and angle [alpha] slides freely on a horizontal plane. A particle of mass m moves freely on the wedge. Determine the motion of the particle as well as that of the wedge.

Note: We are supposed to use the Lagrangian formulation of mechanics to solve this problem.

The Attempt at a Solution


Okay, here's what I've got so far:

We can write the position of the mass m as

x = l cos [alpha];
y = l sin [alpha]

where l is the length of the hypotenuse of the wedge that the mass is sliding on.

Thus, the kintetic energy of the mass m is equal to [(1/2)m][l^2 cos^2(alpha) - l^2 sin^2(alpha)]; the potential energy is equal to [l sin(alpha)][mg]. Therefore, the Lagrangian can be written as

L = [(1/2)l^2m(cos^2(alpha) - sin^2(alpha))] - [l sin(alpha)][mg].

And that's as far as I've gotten; I'm having trouble with the rest. Help is appreciated greatly.
 
Physics news on Phys.org
You need to consider the motion of the wedge. There are two independent degrees of freedom here: the horizontal position of the wedge, and the height of the mass on the wedge. Everything else (such as the horizontal position of the mass) can be expressed in terms of these two.
 
Avodyne said:
You need to consider the motion of the wedge. There are two independent degrees of freedom here: the horizontal position of the wedge, and the height of the mass on the wedge. Everything else (such as the horizontal position of the mass) can be expressed in terms of these two.

How do I specify the position of the wedge? It's moving freely on a horizontal plane; it doesn't seem like there's a way to tell exactly where it is (at least to me).
 

Similar threads

Replies
6
Views
2K
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
12
Views
3K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
Replies
6
Views
4K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K