Laura W
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I've been given this:
x''+ x = 4δ(t-2π)
The question asks:
With initial conditions of x(0) = 1 and x'(0) = 0, find x(t) using Laplace transforms.
I can easily get it to this:
4(sin(t-2π)u(t-2π))
But the question says "express your final solution without use of the unit step function". This is where I get confused as I'm not quite sure as to how to do that. Will it just be 4sin(t)? Considering the sin function repeats at 2π.
x''+ x = 4δ(t-2π)
The question asks:
With initial conditions of x(0) = 1 and x'(0) = 0, find x(t) using Laplace transforms.
I can easily get it to this:
4(sin(t-2π)u(t-2π))
But the question says "express your final solution without use of the unit step function". This is where I get confused as I'm not quite sure as to how to do that. Will it just be 4sin(t)? Considering the sin function repeats at 2π.