UV Light Penetration: Explaining Heuristic of Photopolymers

AI Thread Summary
Longer wavelengths of UV light penetrate photopolymers more deeply than shorter wavelengths, as demonstrated by the difference in penetration between UVA and UVC spectra. This phenomenon can be explained through the interaction of photons with the material, where longer wavelengths have a higher probability of passing through without colliding with particles, akin to a skier navigating a slalom course with fewer turns. However, the penetration of UV light is highly material-specific, and understanding the chemical structure and composition of the photopolymer is crucial for accurate analysis. The physics of light transport in materials is complex and is a significant area of study in solid state and condensed matter physics, with various optical diagnostics employed to explore these properties, including the phonon spectrum, which influences characteristics like transparency and absorption depth.
sdhpg
Messages
2
Reaction score
0
For a photopolymer, the heuristic goes that longer wavelengths of UV light penetrate deeper than shorter wavelengths of UV light. For example, the UVA spectrum penetrates more deeply into the photopolymer than the UVC spectrum. What is the best way for this to be explained?
 
Chemistry news on Phys.org
This question has already been addressed here:
https://www.physicsforums.com/threads/wavelength-and-penetration.350432/

The answers given are very technical, however, and I am not as clever as many here, so I am very prepared to be corrected if I am wrong. Some years ago, I read Richard Feynman's book QED. If I understood correctly, as photons pass through a medium, such as glass, some will strike a particle within the material and be reflected, and some will pass through without striking anything. This is why we can see a reflection in glass as well as seeing through it.

Now, when its wavelength is longer, a photon has a greater probability of passing through without striking anything. This could be illustrated by a skier on a slalom course. If he is skiing with a "long wavelength", for example, if he only has to turn at every fourth flag, he would be less likely to collide with one within a given distance than he would if he was skiing with a "short wavelength", as when he must make a turn around every flag.

The case with a polymer would be different to glass, in that it is not as transparent to photons. Nevertheless, there is still a greater probability of the photon avoiding a collision for longer if its wavelength is longer.
 
sdhpg said:
For a photopolymer, the heuristic goes that longer wavelengths of UV light penetrate deeper than shorter wavelengths of UV light. For example, the UVA spectrum penetrates more deeply into the photopolymer than the UVC spectrum. What is the best way for this to be explained?

UV light's "penetration" by wavelength is very material specific and without clear details about the photo-polymers chemical structure (polymers) and composition (additives), no more can be said.
 
What is needed here is the phonon spectrum of the material.

The physics of light transport in a material is not trivial, and it is dealt with in solid state/condensed matter physics. In fact, the use of optical spectra in the study of material is a well-established area of study within this field of physics. Many optical diagnostics such as Raman, UV-VIS, FTIR, etc. use the properties of light transport in solids to extra information such as the phonon structure of the material. The optical mode of the phonon structure, for example, greatly influences light transport in that material, often producing significant characteristics such as transparency, penetration depth, absorption bandwidth, etc.

Zz.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top