Variable mass problem (integration help)

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SUMMARY

The discussion centers on solving the variable mass problem involving a uniform chain of length L and density ρ on a frictionless table. The user presents their integral, \int \sqrt{(y^{2}-y^{2}_{o})g/l}^{-1/2}, and arrives at two potential solutions involving the arccosh function and logarithmic expressions. A key point of contention is the square root of the term l/g, which is essential for maintaining the correct dimensionality of time in the final answer. The user confirms that l/g must indeed be square rooted to ensure dimensional consistency.

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Homework Statement



I've pretty much solved it, but I'm unsure of my final integration

A uniform chain of length L and density /rho(kg/m) is initially stationary on a horizontal, frictionless table, with part of the chain (length yo) hanging over the edge. How much time passes before the entire chain has left the table?


Homework Equations



arccosh(x) = log(sqrt(x2-1)+x)


The Attempt at a Solution




I don't think i need to put all the work I've done.


my integral

[tex]\int \sqrt{(y^{2}-y^{2}_{o})g/l}^{-1/2}[/tex]

the answer i get is

[tex]arccosh( \sqrt{l/g}*y/y_{o})[/tex]

or

[tex]\sqrt{l/g}*log(2(\sqrt{y^{2}-y^{2}_{o}}+y))[/tex]

yet on wolfram and other websites they say that l/g should not be square rooted. Yet i don't see why.

thanks
 
Physics news on Phys.org
L/g has to be square rooted. If not, the dimension of the time is wrong.

ehild
 
ah yes, thank you. I should have noticed that
 

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