Vector and scalar magnitude problem

AI Thread Summary
To solve for the x component and magnitude of vector A given that vector -1.90A has a magnitude of 59.1 m and points in the positive x direction, it is essential to recognize that vector A points in the opposite direction. The magnitude of vector A can be calculated by dividing the magnitude of -1.90A by 1.90, which yields a value of approximately 31.1 m. The x component of vector A will be negative since it points in the opposite direction to -1.90A. The confusion arises from the interpretation of the negative sign and the calculations, which need to be carefully checked for accuracy. Proper understanding of vector direction and magnitude is crucial for solving this problem correctly.
lsu777
Messages
7
Reaction score
0

Homework Statement



The vector -1.90A has a magnitude of 59.1 m and points in the positive x direction. Calculate the x component of the vector A.

Calculate the magnitude of the vector A.


Homework Equations





3. The Attempt at a Solution

I understand vectors but having a problem understanding how to set this problem up. this is the last problem of a 20 problem set and is the only one I can't figure out. would appreciate any help ya'll could provide.
 
Physics news on Phys.org
I think you just use basic algebra for this.

-1.90 A is 1.9 times the length of vector A, and points in the opposite direction as vector A. So what direction does vector A point in, and what's its length?
 
doesnt give me anymore information then what is given. and i tried 59.1/1.9 to give me the answer but it said that was incorrect.
 
Shouldn't it be negative?
 
yea i used the negative. i actually tried both ways and was told both were incorrect. only have one chance left.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top