Vector Calculus, Unit normal to surface help

tarwe
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Homework Statement


If \phi(x,y,z) = x3 + 2xy +yz3 find \nabla\phi at the point P=(1,1,2) and direction of the unit normal to the surface \phi(x,y,z) = 11 at P.

Homework Equations





The Attempt at a Solution


Worked out \nabla\phi to be 5i + 10j + 12k
Got |\nabla\phi|= √256

so the unit normal to surface is surely \frac{5+10+12}{√269}
but how does the =11 bit make a difference?

Thanksss
 
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welcome to pf!

hi tarwe! welcome to pf! :smile:
tarwe said:
but how does the =11 bit make a difference?

it doesn't :wink:

(btw, it's not 256)
 


tiny-tim said:
hi tarwe! welcome to pf! :smile:


it doesn't :wink:

(btw, it's not 256)


thank you!
that was a typo, meant 269, was thinking in binary :/
 
tarwe said:

Homework Statement


If \phi(x,y,z) = x3 + 2xy +yz3 find \nabla\phi at the point P=(1,1,2) and direction of the unit normal to the surface \phi(x,y,z) = 11 at P.

Homework Equations


The Attempt at a Solution


Worked out \nabla\phi to be 5i + 10j + 12k
Got |\nabla\phi|= √256

so the unit n0ormal to surface is surely \frac{5+10+12}{√269}
You mean \frac{5i+10j+12k}{√269}

but how does the =11 bit make a difference?
It would change the exact position but not the normal to the surface.

Thanksss

Homework Statement


Homework Equations


The Attempt at a Solution

 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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