- #1
Cpt Qwark
- 45
- 1
Homework Statement
Given a×b=-i-j+3k and c×a=2i-3j+k, find a×(a-2b+c)
Homework Equations
Cross product (DONE WITHOUT MATRICES).
The Attempt at a Solution
a[/B]×b=c=-(b×a)is all I'm getting to at this point
Simply distribute the cross-product.Cpt Qwark said:Homework Statement
Given a×b=-i-j+3k and c×a=2i-3j+k, find a×(a-2b+c)
Homework Equations
Cross product (DONE WITHOUT MATRICES).
The Attempt at a Solution
a[/B]×b=c=-(b×a)is all I'm getting to at this point
No. Not at all.Cpt Qwark said:Thanks,
so would I have to find the components of a, b, and c?
Cpt Qwark said:Thanks,
so would I have to find the components of a, b, and c?
A vector cross product is a mathematical operation that takes two vectors as inputs and outputs a third vector that is perpendicular to both of the input vectors. It is commonly used in physics and engineering to calculate forces and torque.
To find the cross product of two vectors, you first need to make sure that the two vectors are in the same dimension. Then, you can use the cross product formula, which is a×b = (a2b3 - a3b2, a3b1 - a1b3, a1b2 - a2b1). Plug in the values for each component of the vectors, and the resulting vector will be the cross product.
The "a-2b+c" represents the second vector that is being used in the cross product calculation. The "a" and "c" are the components of the first vector, while the "2b" means that the second vector is being multiplied by a scalar value of 2.
The resulting vector is perpendicular to the input vectors because of the mathematical properties of the cross product. The cross product of two vectors is always perpendicular to both of the input vectors, creating a 90-degree angle between them.
The vector cross product has many real-life applications, such as calculating torque in physics, determining the direction of magnetic fields, and designing 3D graphics in computer science. It is also used in engineering for calculating forces and moments in structures and machinery.