Vector Equation: Line Parallel 2i-10j-8k Through (5,-1,6)

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To determine the vector equation of a line parallel to the vector 2i-10j-8k and passing through the point (5, -1, 6), the equation can be expressed as r = (5i - j + 6k) + λ(2i - 10j - 8k), where λ is a scalar parameter. The equation format may be unfamiliar, but it effectively represents the line in vector form. The mention of "lambda" indicates the parameter used to describe points along the line. Clarification is needed on the format, as traditional equations typically include an equals sign. Understanding this vector representation is essential for solving the problem correctly.
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1. Determine the vector equation of the line which is parallel to the vector 2i-10j-8k and which passes through the point (5, -1, 6).
2. vector equation
3. 2i-10j-8k (5, -1, 6)
5i-j+6k+landa(2i-10j-8k)

Is this all I need to do to complete this question, please?
 
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I'm sorry i don't understand what the question is. I have never seen this format for any vector equation
 
lemon said:
1. Determine the vector equation of the line which is parallel to the vector 2i-10j-8k and which passes through the point (5, -1, 6).



2. vector equation



3. 2i-10j-8k (5, -1, 6)
5i-j+6k+landa(2i-10j-8k)

Is this all I need to do to complete this question, please?
lemon said:
Determine the vector equation
I don't see an equation - an equation always has = in it. Also, this Greek letter - \lambda - is named "lambda."
 

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