Vector function, position and tangent vectors

Maianbarian
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Homework Statement


If a curve has the property that the position vector r(t) is always perpendicular to the tangent vector r'(t) show that the curve lies on a sphere with center at the origin


Homework Equations



The Attempt at a Solution



I have no idea how to even approach this problem, if somebody could give me a nudge in the right direction it would be much appreciated.
 
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Differentiate r(t).r(t) (the dot product).
 
Ah, I get it now.

We know that r(t).r(t)=|r(t)|^2. Differentiating the dot product we get:

d/dt [r(t).r(t)]= 2r'(t).r(t) = 0 (as r'(t) is orthogonal to r(t))

thus |r(t)|^2 is constant, and so |r(t)| is constant, which corresponds to a sphere with the centre at the origin.

Thanks Dick :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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