Vector Functions: Show Limit as t Goes to a

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Homework Statement



Show that the lim r(t)=b as t goes to a if and only if for every \epsilon>0 there is a number \delta>0 such that |r(t) - b| < \epsilon whenever 0<|t-a|<\delta

Homework Equations



if r(t) = <f(t),g(t),h(t)>, then

limr(t) as t goes to a = <limf(t) as t goes to a, limg(t) as t goes to a, limh(t) as t goes to a>
I really have no idea on how to go about this problem
 
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haello aesailor! :wink:

(have a delta: δ and an epsilon: ε :wink:)

For each ε you have three δs …

but you need only one δ, so … ? :smile:
 
I'm really confused by your response tiny tim
 
For a particular ε, you have three δs (δf δg and δh, say) one for f, one for g, and one for h.

So the least of these will work for all three of f g and h. :wink:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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