Calculating Airplane Velocity with Wind: A Study

AI Thread Summary
To calculate the resultant velocity of the airplane over the ground with wind, the initial velocity of the plane and the wind's velocity must be vectorially added. For part a, the resultant velocity can be determined using vector addition, which combines the airplane's velocity and the wind's effect. For part b, to maintain the same heading and speed, the pilot needs to adjust the airplane's direction to counteract the wind's influence, effectively creating a new heading that compensates for the wind. The discussion highlights confusion regarding the adjustment needed for the airplane's heading in response to wind conditions. Understanding vector addition is crucial for solving both parts of the problem effectively.
soccer5
Messages
2
Reaction score
0

Homework Statement



An airplane is flying at [80.0, 50.0(degrees)] m/s when there is no wind. Then the wind begind to blow at [18.0, -20 (degrees)] m/s.

a) if the pilot does not change the heading of the plane what will be the resultant velocity over the ground?

b) In order to maintain the same heading and speed as before, how should the pilot now direct the plane??



The Attempt at a Solution



I know how to do part a.
But i have no clue about part b
please help??
 
Physics news on Phys.org
Any ideas/attempts?
 
no idea.
we never did anything like that in class.
 
Well, you only have to regard the "same speed and heading as before" as the resultant velocity of the plane in case b).
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top