- #1
Bassa
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Hello! I have a problem in my calculus based physics class regarding vectors. The problem says:
Vectors A and B have a scalar product -6.00 and their vector product has magnitude 9.00 what is the angle between these two vectors?
Here is how I approached it:
-6=|A||B|cos (theta)
9=|A||B|sin (theta)
tan (theta)= sin (theta)/cos (theta)
tan (theta)=9/-6=-56.31 degrees
since the sine is positive and cosine is negative the angle lies in the second quadrant.
180 degrees -56.31 degrees= 123.69 degrees which is approximately 124 degrees.
Now, why does the angle between the scalar product and the vector product of A and B give us the angle between A and B?
Thanks!
Vectors A and B have a scalar product -6.00 and their vector product has magnitude 9.00 what is the angle between these two vectors?
Here is how I approached it:
-6=|A||B|cos (theta)
9=|A||B|sin (theta)
tan (theta)= sin (theta)/cos (theta)
tan (theta)=9/-6=-56.31 degrees
since the sine is positive and cosine is negative the angle lies in the second quadrant.
180 degrees -56.31 degrees= 123.69 degrees which is approximately 124 degrees.
Now, why does the angle between the scalar product and the vector product of A and B give us the angle between A and B?
Thanks!