Vector Valued Function Spaceship Problem

Baumer8993
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Homework Statement



The position function of a spaceship is r(t)= < 3+T, 2+ln(T), 7 -(4/T2+1)> , and the coordinates of a space station are (6, 4, 9). The captain wants to coast into the space station. When should the engines be turned off?

Homework Equations


I took the derivative of the position function to get the velocity function:
V(t)= <1, (1/T), (8T)/(T2+1)2


The Attempt at a Solution



Right now I have a vector I called U =<6-3+s>, 4 -(2+ln(s)), 9-[7-(4/s2+1)]
I got this hint from my professor. I understand that this is the position vector to the spaceship at time s. I know I now need to find the velocity vector that is parallel to the position vector. My professor gave me the hint to multiply by a constant K in the velocity vector function. At that point I would have two equations, and two unknowns which is easy to solve. I am just stuck on when I multiply by the constant K what would I set the velocity vector function equal too?
 
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When the engines are switched off, the spaceship will probably move in a straight line. So you want to switch them off when your velocity vector points from r(t) towards the space station.
 
This is a repost of

https://www.physicsforums.com/showthread.php?t=667299

Why are you reposting a question that has already been replied to?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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