Vector Valued Function Spaceship Problem

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SUMMARY

The discussion revolves around determining when a spaceship should turn off its engines to coast into a space station located at coordinates (6, 4, 9). The position function is given by r(t) = <3 + T, 2 + ln(T), 7 - (4/T² + 1)>, and the velocity function derived from it is V(t) = <1, (1/T), (8T)/(T² + 1)²>. The key to solving the problem lies in finding a constant K that allows the velocity vector to be parallel to the position vector directed towards the space station.

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Homework Statement



The position function of a spaceship is r(t)= < 3+T, 2+ln(T), 7 -(4/T2+1)> , and the coordinates of a space station are (6, 4, 9). The captain wants to coast into the space station. When should the engines be turned off?

Homework Equations


I took the derivative of the position function to get the velocity function:
V(t)= <1, (1/T), (8T)/(T2+1)2


The Attempt at a Solution



Right now I have a vector I called U =<6-3+s>, 4 -(2+ln(s)), 9-[7-(4/s2+1)]
I got this hint from my professor. I understand that this is the position vector to the spaceship at time s. I know I now need to find the velocity vector that is parallel to the position vector. My professor gave me the hint to multiply by a constant K in the velocity vector function. At that point I would have two equations, and two unknowns which is easy to solve. I am just stuck on when I multiply by the constant K what would I set the velocity vector function equal too?
 
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When the engines are switched off, the spaceship will probably move in a straight line. So you want to switch them off when your velocity vector points from r(t) towards the space station.
 
This is a repost of

https://www.physicsforums.com/showthread.php?t=667299

Why are you reposting a question that has already been replied to?
 

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