- #1

SigmaCrisis

- 15

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Anyone? Thanks.

I really just need some hint(s) for this.

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- Thread starter SigmaCrisis
- Start date

- #1

SigmaCrisis

- 15

- 0

Anyone? Thanks.

I really just need some hint(s) for this.

- #2

whozum

- 2,221

- 1

- #3

SigmaCrisis

- 15

- 0

Umm, sorry, but could you elaborate? I don't quite get it...new to Calc III.

- #4

mathwonk

Science Advisor

Homework Helper

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Thus if P,Q,R are 3 points, spanning a plane, the two vectors Q-P and Q-R are both parellel to that plane.

then there is a construction called cross product for finding sa vector perpendiculr to two given vectors. hence perpendiculr to the plane they are parallel to.

thus (Q-P) x (Q-R) is perpendicualr to the plane spanned by P,Q,R.

- #5

SigmaCrisis

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Thanks a bunch!

- #6

SigmaCrisis

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One more thing, I'm also asked to find the area of the triangle PQR.

- #7

Astronuc

Staff Emeritus

Science Advisor

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Then what is the relationship of the area of the parallelogram to the triangle formed by the two sides, e.g. PQ, PR and the third QR?

- #8

SigmaCrisis

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Thanks a lot.

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