- #1
chaotixmonjuish
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A particle moves in the x-y plane with constant acceleration. At time t = 0 s, the position vector for the particle is d = 1.8 m x + 4.2 m y. The acceleration is given by the vector a = 1.5 m/s2 x + 6.2 m/s2 y. The velocity vector at time t = 0 s is v = 1.7 m/s x - 1.7 m/s y.
What is the magnitude of the position vector at time t = 7.5 s?
I tried setting up two equations:
F(x)=1.8+1.7x+1.5x^2
F(y)=4.2-1.7y+6.2x^2
This yielding something like 340. That answer didn't bode well with lon capa. I'm just not sure how to set up an equation to solve this.
What is the magnitude of the position vector at time t = 7.5 s?
I tried setting up two equations:
F(x)=1.8+1.7x+1.5x^2
F(y)=4.2-1.7y+6.2x^2
This yielding something like 340. That answer didn't bode well with lon capa. I'm just not sure how to set up an equation to solve this.