A particle moves in the x-y plane with constant acceleration. At time t = 0 s, the position vector for the particle is d = 1.8 m x + 4.2 m y. The acceleration is given by the vector a = 1.5 m/s2 x + 6.2 m/s2 y. The velocity vector at time t = 0 s is v = 1.7 m/s x - 1.7 m/s y.(adsbygoogle = window.adsbygoogle || []).push({});

What is the magnitude of the position vector at time t = 7.5 s?

I tried setting up two equations:

F(x)=1.8+1.7x+1.5x^2

F(y)=4.2-1.7y+6.2x^2

This yielding something like 340. That answer didn't bode well with lon capa. I'm just not sure how to set up an equation to solve this.

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# Homework Help: Vectors and Magnitudes

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