Analyzing Displacement, Velocity, and Acceleration of a Bicyclist in a Park

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The discussion focuses on the motion of a bicyclist moving from a position 40.0m east of a flagpole, initially heading south at 10.0m/s, to a position 40.0m north of the flagpole after 30 seconds, now traveling east at the same speed. Key calculations involve determining the magnitude and direction of displacement, average velocity, and average acceleration during this interval. The confusion arises from the change in direction, prompting questions about how the cyclist transitions from moving south to north. Understanding the concepts of displacement and velocity is crucial for solving the problem. The thread emphasizes the importance of analyzing motion in two dimensions to clarify the cyclist's path.
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Homework Statement



At one instant a bicyclist is 40.0m due east of a park's flagpole, going due south with a speed of 10.0m/s. Then 30.0s later, the cyuclist is 40.0m due north of the flagpole going due east with a speed of 10.0 m/s. For the cyclist in this 30.0s interval what are the A.) magnitude and B.) direction of the displacement, the C.) magnitude and direction of the average velocity and D.) the magnitude and direction of the average acceleration

Homework Equations



v=d/t
a=v2-v1/t

The Attempt at a Solution


not sure where to start really
 
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mimsteel said:

Homework Statement



At one instant a bicyclist is 40.0m due east of a park's flagpole, going due south with a speed of 10.0m/s. Then 30.0s later, the cyuclist is 40.0m due north of the flagpole...

I am confused here, how can a person due east who's going south end up in the north?
 
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