Velocity of a Ball Thrown from a Building

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A ball is thrown upward from a 48 m tall building with an initial velocity of 12 m/s, and the discussion focuses on calculating its velocity upon reaching the ground. The correct approach involves using the equation V² = V₀² + 2aΔh, where 'a' is the acceleration due to gravity (-9.81 m/s²) and Δh is the height (-48 m). The final velocity is calculated as approximately 32.95 m/s, regardless of whether the ball is thrown up or down, due to the conservation of energy. The discussion emphasizes the importance of sign conventions in physics equations to avoid confusion. Ultimately, understanding the relationship between initial velocity, height, and acceleration is crucial for solving such problems.
  • #51
yes now its correct
 

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