- #1

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## Homework Statement

What is the speed of a proton whose kinetic energy is 23.0 keV?

1 eV = 1.6e-19 J

23 Kev = 23000 eV = 3.68e-15 J

## Homework Equations

V = Sq. Rt. ( - ((2)(q)(Vba)) / (m))

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- Thread starter mathcrzy
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- #1

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What is the speed of a proton whose kinetic energy is 23.0 keV?

1 eV = 1.6e-19 J

23 Kev = 23000 eV = 3.68e-15 J

V = Sq. Rt. ( - ((2)(q)(Vba)) / (m))

- #2

rock.freak667

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Just sub the values into the formula

- #3

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What is each value? What is q, Vba, and M?

Is M = 1.67e-27 kg ?

And where does the KeV value go?

Is M = 1.67e-27 kg ?

And where does the KeV value go?

- #4

rock.freak667

Homework Helper

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m=mass of a proton which you have. the eV is just another way to express energy.

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