# Velocity of proton

1. Jan 24, 2008

### mathcrzy

1. The problem statement, all variables and given/known data

What is the speed of a proton whose kinetic energy is 23.0 keV?

1 eV = 1.6e-19 J
23 Kev = 23000 eV = 3.68e-15 J

2. Relevant equations

V = Sq. Rt. ( - ((2)(q)(Vba)) / (m))

3. The attempt at a solution

2. Jan 24, 2008

### rock.freak667

Just sub the values into the formula

3. Jan 24, 2008

### mathcrzy

What is each value? What is q, Vba, and M?

Is M = 1.67e-27 kg ?

And where does the KeV value go?

4. Jan 25, 2008

### rock.freak667

$$E_k=\frac{1}{2}mv^2$$

m=mass of a proton which you have. the eV is just another way to express energy.