Verifying the mean value theorum for absolute value function

[silicon_hobo]

Homework Statement

a) Find the average value of the function $$f(x)=|x-1|$$ over [0,2].
b)Verify the mean value theorum for integrals for the function and interval in part (a).

Homework Equations

mean value theorum for integrals: $$\int_a^{b} f(x)dx=f(c)(b-a)$$

mean value theorum for differentials: $$f\prime(c)=\frac{f(b)-f(a)}{b-a}$$

The Attempt at a Solution

http://www.mcp-server.com/~lush/shillmud/int1.10.JPG
I believe part (b) is asking me to use the differential theorum to prove what has been found in part (a) but I'm rarely sure what to do when asked to 'verify' or 'prove'. Am I on the right track in my attempt to use the differential mvt to verify what I have found with the integral mvt in the first part? I know something's not right because the derivative of |x-1| is going to be either 1 or -1 at all times yet I've got an answer of 0 in part (b). Some clarification on how these theories work with regards to this problem would be greatly appreciated. Thanks for reading.

 

[silicon_hobo]

Bump. I'm still stumped on this one.

 

[mellymel21]

Please help if anyone knows this answer.

 

[Mark44]

Please help if anyone knows this answer.

You have reopened a thread that is more than two years old. Per the rules of this forum, you need to show an effort at solving the problem you post. What have you tried?