If the line x=1 is a vertical asymptote of y = f(x), then f is not defined at 1.
The Attempt at a Solution
I originally believed this was true, but on finding it was false it sought a counter example:
if for example f(x) = 1/x if x != 0
5 if x = 0
Then the function is defined, but the asymptote still is at x=1, correct?
This is very basic - I just want to make sure I understand it thoroughly. Thanks.