Very basic acceleration question (typo?)

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An object with an initial velocity of +4 m/s and a constant acceleration of -15 m/s² will reach a speed of zero after approximately 0.267 seconds. The initial calculation of 0.27 seconds was incorrect due to significant digit considerations. The discussion suggests that the problem may have had a typo, but it was clarified that the issue was related to precision in the answer. The correct time for the object to stop is thus confirmed as 0.267 seconds. This highlights the importance of accuracy in calculations involving physics problems.
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An object starts at time t = 0 with a velocity of v = +4 m/s and undergoes a constant acceleration of a = -15 m/s2
At what time does the speed of the object reach zero?

so,
vf = vi + a t
so delta t = 0 - 4 / -15

= .27 seconds

apparentrly this is wrong answer, but I can't see why? seems really simple!

I am suspecting that this question had a typo in it?

Sorry, please disregard, it was sig dig problem
should be .267 seconds!
 
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Thanks for posting this in the Homework Help section mujadeo.
 
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