encorelui2
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Statics: If computing the moment of inertia about the y-axis of a triangular shape in the 2nd quadrant(not touching the x-axis); would i still use hb^3 /12
The discussion centers on calculating the moment of inertia for a triangular shape in the second quadrant using the formula \( \frac{hb^3}{12} \). Participants confirm that this formula is applicable to right triangles and emphasize the importance of correctly identifying the base (b) and height (h) dimensions. The position of the triangle relative to the x-axis does not affect the formula's validity, provided one side is collinear with the y-axis. Additional resources for area properties of general triangular shapes are also provided.
PREREQUISITESStudents and professionals in engineering, particularly those focusing on statics, structural analysis, and mechanical design, will benefit from this discussion.
encorelui2 said:Statics: If computing the moment of inertia about the y-axis of a triangular shape in the 2nd quadrant(not touching the x-axis); would i still use hb^3 /12
nvn said:encorelui2: So far, your formula looks correct. And, it is not limited to right triangles.
It does not matter whether it touches the x-axis or not. And it does not matter what quadrant it is in. It only needs to have one side coincident (collinear) with the y axis, assuming b is the horizontal width of your triangle.