Very simple gravity/time/distance travelled problem

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To calculate the time (t2) for a droplet to fall from point X to point B, first determine the time (t[X]) it takes to reach point X using the equation t1=square_root((2 * d)/g), where d is the distance from A to B and g is the acceleration due to gravity. Since the droplet has a certain speed when it reaches point X, t2 cannot be calculated using the same equation directly. Instead, subtract t[X] from the total time t1 to find t2. This approach is essential for high-speed photography of falling objects.
dkayuk
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Homework Statement


This isn't really homework, because I'm not at school anymore (aged 42!) but I will describe as best as I can.

A small object like a droplet of water is released from a height (point A), falling on the surface (Point B) with initial speed 0. Distance between A and B, I will call d and obviously there's gravity (g) and time it takes for the droplet to fall from A to B, I will call t1. I know the equation so that given d is known, and so is gravity, then I can calculate time (t1).

Suppose that between points A and B, there's a point X. By the time the droplet has reached X is already has a certain speed. How do I calculate the time (t2) that it takes for the droplet to travel from X to the surface (B)?

Homework Equations



t1=square_root((2 * d)/g)

The Attempt at a Solution



I know (or at least I think I know) that I can't use the same equation to calculate t2 because the droplet already has a certain speed.

Apologies, if I'm not explaining this very well. I've not done any physics for 25 years and the reason I need this is because I'm doing high speed photography with falling objects.

thx

DK
 
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If you know the distance AX, you can use the above equation to calculate the time for the droplet to reach point X, t[X]. As t[1] stays the same whether or not you add an extra reference point, simply substract t[X] from t[1] and you have your answer.

Hope this helps.
 
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