stevendaryl said:
I'm a little puzzled by your paper, because it seems to contradict what I understood about Bell's theorem. You say that it is the assumption of particles that causes problems, but it seems to me that in Bell's derivation, there is no specific assumption about particles. Instead, he's assuming that if you have two measurements A and B, each of which gives result \pm 1, that take place at a spacelike separation (so there is no possibility of one influencing the other), then the probability that A=B=1 is given by an expression:
\sum_\lambda P(\lambda) P(A=1|\alpha, \lambda) P(B=1|\beta, \lambda)
where \alpha represents whatever state variables are local to A, \beta represents the state variables local to B, and \lambda represents state variables that are in the common backward lightcone of A and B. I don't see that particles specifically come into it.
Particles come into it in the following way:
In order to prove that a violation of Bell's inequality precludes a classical relativistic particle description, one proves the following theorems:
Theorem 1: Every classical relativistic
particle theory implies that probabilities are given by the expression \sum_\lambda P(\lambda) P(A=1|\alpha, \lambda) P(B=1|\beta, \lambda).
Theorem 2: Whenever probabilities are given by the expression \sum_\lambda P(\lambda) P(A=1|\alpha, \lambda) P(B=1|\beta, \lambda), Bell's inequality holds.
An experimental violation of Bell's inequality shows that probabilities can't possibly be given by that expression and by the first theorem, this precludes a classical relativistic particle description.
Now if you want to prove that a violation of Bell's inequality precludes a description by classical relativistic fields, you would have to prove the following theorem:
(tentative) Theorem 1': Every classical relativistic
field theory implies that probabilities are given by the expression \sum_\lambda P(\lambda) P(A=1|\alpha, \lambda) P(B=1|\beta, \lambda).
Apparently, the paper from the OP provides a counterexample to this (tentative) theorem, so a violation of Bell's inequality doesn't preclude a description by classical relativistic fields.
It is important to note that theorem 2 (Bell's theorem) on its own does not preclude such descriptions and it is always required to have a theorems like 1 and 1' to establish the preclusion of the respective descriptions. Unfortunately, quantum theory books usually just prove theorem 2 and assume that theorem 1 is trivial. However, a real mathematical proof requires the discussion of the causal structure of spacetime and the tools for its study are usually part of an advanced treatment of GR, rather than a course on QM. Nevertheless, theorem 1 can be proven rigorously. However, theorem 1' seems to be invalid, as the paper from the OP shows. I haven't studied it thoroughly, but the math seems to be alright to me. (The answer in the thread Truecrimson linked misses the point.)