Voltage Drop in Parallel Receptacle Wiring

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Homework Help Overview

The discussion revolves around understanding voltage drop in parallel receptacle wiring, specifically in the context of a refrigerator requiring 3 A at 110 V while being supplied by a power plant that also provides 110 V. Participants explore the implications of voltage drop across both the refrigerator load and the resistance of the wiring.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question how a voltage drop can occur across the refrigerator load when there is also a voltage drop across the wiring resistance. Some express confusion about the voltage supply from the power plant and its implications for the problem setup. Others note the absence of specific voltage values for transmission lines and discuss the relevance of these details to the problem.

Discussion Status

The discussion is active, with participants raising questions about the assumptions in the problem statement. Some suggest that the problem may not reflect real-life scenarios and propose that it is focused on calculating power needed to overcome additional resistance. There is exploration of the concept of appliances being wired in parallel and how this relates to voltage across them.

Contextual Notes

Participants note that certain parameters, such as the resistance of the wiring and the voltage at different points in the distribution system, are not provided in the problem statement, which may affect their ability to make accurate estimates.

annamal
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Homework Statement
A physics student has a single-occupancy dorm room. The student has a small refrigerator that runs with a current of 3.00 A and a voltage of 110 V, a lamp that contains a 100-W bulb, an overhead light with a 60-W bulb, and various other small devices adding up to 3.00 W. (a) Assuming the power plant that supplies 110 V electricity to the dorm is 10 km away and the two aluminum transmission cables use 0-gauge wire with a diameter of 8.252 mm, estimate the percentage of the total power supplied by the power company that is lost in the transmission.
Relevant Equations
P = ##I^2 R##
V = IR
I know how to solve the question but I am a bit confused about why there is a current of 3 A and a voltage of 110 V requirement for the refrigerator but the power plant only supplies 110 V.

How can there be a voltage drop on the refrigerator load of 110 V, when there is also a voltage drop on the resistance of the wire which this load is in series with?
 
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annamal said:
How can there be a voltage drop on the refrigerator load of 110 V, when there is also a voltage drop on the resistance of the wire which this load is in series with?
It says "the power plant ... supplies 110 V electricity to the dorm", not that it generates 110V.
 
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It isn't needed -- it isn't in the Relevant Equation.
 
russ_watters said:
It isn't needed -- it isn't in the Relevant Equation.
But using ## 110 \rm{V} ## is going to be an abominable estimate of the desired measure?

Also, ## R = \rho \frac{L}{A} ## is needed and isn't explicitly listed either as well as some other parameters.
 
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erobz said:
Why isn't the voltage of the transmission lines given in the problem statement I wonder? I think either the voltage at the plant or the voltage at the at the dorm should be given to make a reasonable estimate.
It is not a real life problem.
They just want you to calculate the power needed to overcome that additional resistance, which is in series with the measurable summation load of all the room equipment.

You have the total number of amps flowing in and out the room; therefore, the same amount must flow through that additional resistance (10 km of wires), located between “110 volts” of pushing potential.
 
Lnewqban said:
It is not a real life problem.
They just want you to calculate the power needed to overcome that additional resistance, which is in series with the measurable summation load of all the room equipment.

You have the total number of amps flowing in and out the room; therefore, the same amount must flow through that additional resistance (10 km of wires), located between “110 volts” of pushing potential.
I was thinking it might be a lesson on why transmission lines are high voltage.
 
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haruspex said:
It says "the power plant ... supplies 110 V electricity to the dorm", not that it generates 110V.
Hmm. The appliances each have 110 V across them since the appliances are in parallel with each other?
 
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annamal said:
Hmm. The appliances each have 110 V across them since the appliances are in parallel with each other?
Yep. Its not exactly of consequence here, but that is generally how receptacles are wired. "Ideally" each receptacles is in parallel with the supply. However, they aren't "ideally" wired in parallel ( as in a dedicated set of line to each receptacle from the source ) in reality to save money and construction labor cost.
 
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