Volume of Cube changing with respect to time.

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SUMMARY

The volume of a cube is changing with respect to time, calculated using the formula dv/dt = dx/dt * 3x². At a specific moment when the side length x is 5 inches and increasing at a rate of 0.1 inches per second, the rate of change of the volume (dv/dt) is determined to be 7.5 cubic inches per second. This calculation confirms the correct application of related rates in calculus.

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Homework Statement


The volume V of a cube with sides of length x in. is changing with respect to time. At a certain instant of time, the sides of the cube are 5 in. long and increasing at the rate of 0.1 in./sec. How fast is the volume of the cube changing at that instant of time?




The Attempt at a Solution


dv/dt = dx/dt*3x2
dx/dt=0.1 x=5
dv/dt=0.1(3*52)=7.5 cu in/sec

am i correct in my answer?
 
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Looks right.
 
thanks! :)
 

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