Volume of solid under graph and above circular region

DSnead
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Find the volume of the solid under the graph of z=sqrt(16-x^2-y^2) and above the circular region x^2+y^2<=4 in the xy plane

I know I must go to polar. So z=sqrt(16-r^2). Does r range from 0-2? I am not sure what theta ranges from (0-2pi)? I set up the integral as int(int r*sqrt(16-r^2), r=0..2), theta=0..2pi) but I get nowhere near any of the answer choices.
 
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Welcome to PF!

Hi DSnead! Welcome to PF! :smile:
DSnead said:
… I know I must go to polar …

No, just divide into horizontal slices of thickness dz, and integrate over z. :wink:
 

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