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frank1
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Homework Statement
Whats the stock solution volume required to prepare 100ml of a NaHCO3 solution 5g/L using a stock solution of NaHCO3 30g/L.
Homework Equations
M1*V1 = M2*V2
M = Molarity = mols/L
The Attempt at a Solution
NaHCO3 = 84g/mol
5g NaHCO3 = 0.0595238095238095mol
30g NaHCO3 = 0.3571428571428571mol
M1*V1 = M2*V2 => 0.0595238095238095*0.1 = 0.3571428571428571*V2
V2 = 0.01666L = 16,7mL
But the answer is 3,33 mL