1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Volume of the solid region with respect to x,y-axises, and lines x and y work shown

  1. Feb 25, 2009 #1
    Indicate the method you use to set up the integrals (do not integrate) that give the volume of the solid generated by rotating the region R around:

    The region R is bounded by the curves y=x, x= 2-y^2 and y=0

    i.) the x-axis
    ii.) the y-axis
    iii.) the line x= -2
    iv.) the line y= 1

    work shown:

    y=x ,

    x= 2- y^2
    y= sqrt(2-x)

    i.) integral of Pi*[(x)- (sqrt(2-x))] dx as x goes from 0 to 1

    ii.) integral of 2*Pi*x*[(x)-sqrt(2-x)]dx as y goes from 0 to 1

    iii.) integral of 2*Pi*(-2-x)*[(x)-(sqrt(2-x))]dx as x goes from 0 to 1

    iv.) integral of Pi*[(x-1)-(sqrt(2-x-1)]dx as y goes from 0 to 1

    I think my definite integral limits are wrong... and in general my integral setup is wrong.. please help
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?



Similar Discussions: Volume of the solid region with respect to x,y-axises, and lines x and y work shown
Loading...