# Volume of the solid region with respect to x,y-axises, and lines x and y work shown

1. Feb 25, 2009

### johnq2k7

Indicate the method you use to set up the integrals (do not integrate) that give the volume of the solid generated by rotating the region R around:

The region R is bounded by the curves y=x, x= 2-y^2 and y=0

i.) the x-axis
ii.) the y-axis
iii.) the line x= -2
iv.) the line y= 1

work shown:

y=x ,

x= 2- y^2
y= sqrt(2-x)

i.) integral of Pi*[(x)- (sqrt(2-x))] dx as x goes from 0 to 1

ii.) integral of 2*Pi*x*[(x)-sqrt(2-x)]dx as y goes from 0 to 1

iii.) integral of 2*Pi*(-2-x)*[(x)-(sqrt(2-x))]dx as x goes from 0 to 1

iv.) integral of Pi*[(x-1)-(sqrt(2-x-1)]dx as y goes from 0 to 1

I think my definite integral limits are wrong... and in general my integral setup is wrong.. please help
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted