Volume of vessel occupied by molecules

AI Thread Summary
In a closed vessel containing a mixture of atomic and molecular oxygen, the volume occupied by each species is indeed equal to the total volume V of the vessel. According to Dalton's Law of Partial Pressures, each gas in the mixture exerts pressure as if it occupies the entire volume independently. This means that the pressure calculated for each gas assumes it fills the whole volume V. Therefore, the volume occupied by each species in the mixture is considered to be V when determining their pressures. Understanding this principle is crucial for solving related gas law problems.
Amith2006
Messages
416
Reaction score
2

Homework Statement


Suppose a closed vessel of volume V contains a mixture of atomic and molecular Oxygen. Will the volume of the vessel occupied by each species be equal to V? I have this doubt because in my book in order to determine the pressure exerted by each species they have taken the volume as V in each case.


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
by dalton's law of partial pressures, in a mixture of gases, pressure by each gas is equivalent to the the pressure it would exert if it fills up the whole volume itself.
So, same volume is considered (in this case, V)
 
f(x) said:
by dalton's law of partial pressures, in a mixture of gases, pressure by each gas is equivalent to the the pressure it would exert if it fills up the whole volume itself.
So, same volume is considered (in this case, V)

Thanks buddy.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top